4[x+(3-2x)]+5=3(x+11)

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Solution for 4[x+(3-2x)]+5=3(x+11) equation:


Simplifying
4[x + (3 + -2x)] + 5 = 3(x + 11)

Remove parenthesis around (3 + -2x)
4[x + 3 + -2x] + 5 = 3(x + 11)

Reorder the terms:
4[3 + x + -2x] + 5 = 3(x + 11)

Combine like terms: x + -2x = -1x
4[3 + -1x] + 5 = 3(x + 11)
[3 * 4 + -1x * 4] + 5 = 3(x + 11)
[12 + -4x] + 5 = 3(x + 11)

Reorder the terms:
12 + 5 + -4x = 3(x + 11)

Combine like terms: 12 + 5 = 17
17 + -4x = 3(x + 11)

Reorder the terms:
17 + -4x = 3(11 + x)
17 + -4x = (11 * 3 + x * 3)
17 + -4x = (33 + 3x)

Solving
17 + -4x = 33 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
17 + -4x + -3x = 33 + 3x + -3x

Combine like terms: -4x + -3x = -7x
17 + -7x = 33 + 3x + -3x

Combine like terms: 3x + -3x = 0
17 + -7x = 33 + 0
17 + -7x = 33

Add '-17' to each side of the equation.
17 + -17 + -7x = 33 + -17

Combine like terms: 17 + -17 = 0
0 + -7x = 33 + -17
-7x = 33 + -17

Combine like terms: 33 + -17 = 16
-7x = 16

Divide each side by '-7'.
x = -2.285714286

Simplifying
x = -2.285714286

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